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3-2.Motion in Plane
easy
An electric fan has blades of length $30 \,cm$ as measured from the axis of rotation. If the fan is rotating at $1200\,$ r.p.m. , the acceleration of a point on the tip of the blade is about .......... $m/sec^2$
A$1600$
B$4740$
C$2370$
D$5055$
(AIPMT-1990)
Solution
Acceleration$=\omega^{2} R=(2 \pi f)^{2} R$
$=\left(2 \times \frac{22}{7} \times \frac{1200}{60}\right)^{2} \times \frac{30}{100}$
$=4740 ms ^{-2}$
$=\left(2 \times \frac{22}{7} \times \frac{1200}{60}\right)^{2} \times \frac{30}{100}$
$=4740 ms ^{-2}$
Standard 11
Physics
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