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10-1.Thermometry, Thermal Expansion and Calorimetry
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An electric kettle (rated accurately at $2.5\, kW$) is used to heat $3\, kg$ of water from $15\,^oC$ to boiling point. It takes $9.5$ minute. Then, the amount of heat that has been lost is
A
$3.5\times10^5\, J$
B
$7\times10^6\, J$
C
$3.5\times10^4\, J$
D
$7\times10^8\, J$
Solution
Energy consumed in $9.5$ min
$=2.5 \times 1000 \times 9.5 \times 60 \mathrm{J}$
$=1425000 \mathrm{J}$
Heat usefully consumed
$=3 \times 4.2 \times 1000 \mathrm{m} \times(100-15) \mathrm{joule}$
$=1071000$ joule
Loss $=3.5 \times 10^{5}$ joule
Standard 11
Physics
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