Find the quantity of heat required to convert $40\; gm$ of ice at $-20^{\circ} C$ into water at $20^{\circ} C$. Given $L _{\text {ice }}$ $=0.336 \times 10^6 J / kg$.
specific heat of ice $=2100 \;J / kg - K$ sp heat of water= $4200\; J / kg - K$
$18480$
$17580$
$18685$
$17412$
If mass energy equivalence is taken into account, when water is cooled to form ice, the mass of water should
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