An electron (charge q coulomb ) enters a magnetic field of H weber/{m^2} with a velocity of v,m/s in

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4.Moving Charges and Magnetism

easy

An electron (charge $q$ $coulomb$) enters a magnetic field of $H$ $weber/{m^2}$ with a velocity of $v\,m/s$ in the same direction as that of the field the force on the electron is

A

$Hqv$ Newton’s in the direction of the magnetic field

B

$Hqv$ dynes in the direction of the magnetic field

C

$Hqv$ Newton’s at right angles to the direction of the magnetic field

D

Zero

Solution

(d) $\overrightarrow F = q(\overrightarrow {v\,} \times \overrightarrow B ) = 0$ as $\overrightarrow {v\,} $ and $\overrightarrow B $ are parallel.

Standard 12

Physics

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