4.Moving Charges and Magnetism
medium

An electron having mass $m$ and kinetic energy $K$ enter in uniform magnetic field $B$ perpendicularly, then its frequency will be

A

$\frac{e K}{q v B}$

B

$\frac{e B}{2 \pi m}$

C

$\frac{2 \pi m}{e B}$

D

$\frac{2 m}{e B K}$

(AIPMT-2001)

Solution

$\frac{ mv ^{2}}{ r }= qV B$

$\frac{ mv }{ r }= qB$

$m\omega = qB$

$\omega = qB / m$

$f =\frac{ qB }{2 \pi m }$

Standard 12
Physics

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