An electron is projected with velocity $\vec v$ in a uniform magnetic field $\vec B$ . The angle $\theta$ between $\vec v$ and $\vec B$ lines between $0^o$ and $\frac{\pi}{2}$ . It velocity $\vec v$ vector returns to its initial value in time interval of
$\frac{2 \, \pi m}{eB}$
$\frac{ \pi m}{eB}$
$\frac{ \pi m}{2\,eB}$
Depends upon angle between $\vec v$ and $\vec B$
An electron, moving in a uniform magnetic field of induction of intensity $\vec B,$ has its radius directly proportional to
A beam of well collimated cathode rays travelling with a speed of $5 \times {10^6}\,m{s^{ - 1}}$ enter a region of mutually perpendicular electric and magnetic fields and emerge undeviated from this region. If $| B |=0.02\; T$, the magnitude of the electric field is
A electron $(q = 1.6 \times 10^{-19}\, C)$ is moving at right angle to the uniform magnetic field $3.534 \times 10^{-5}\, T$. The time taken by the electron to complete a circular orbit is......$µs$
An electron is moving with a speed of ${10^8}\,m/\sec $ perpendicular to a uniform magnetic field of intensity $B$. Suddenly intensity of the magnetic field is reduced to $B/2$. The radius of the path becomes from the original value of $r$
A charged particle of mass $m$ and charge $q$ travels on a circular path of radius $r$ that is perpendicular to a magnetic field $B$. The time taken by the particle to complete one revolution is