Gujarati
Hindi
11.Thermodynamics
normal

An engine is supposed to operate between two reservoirs at temperature $727^oC$ and $227^oC.$ The maximum possible efficiency of such an engine is

A

$1/2$

B

$1/4$

C

$3/4$

D

$1$

Solution

$\eta=\frac{T_{1}-T_{2}}{T_{1}}=\frac{(273+727)-(273+227)}{273+727}$

$=\frac{100-500}{1000}=\frac{1}{2}$

Standard 11
Physics

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