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11.Thermodynamics
normal
An engine is supposed to operate between two reservoirs at temperature $727^oC$ and $227^oC.$ The maximum possible efficiency of such an engine is
A
$1/2$
B
$1/4$
C
$3/4$
D
$1$
Solution
$\eta=\frac{T_{1}-T_{2}}{T_{1}}=\frac{(273+727)-(273+227)}{273+727}$
$=\frac{100-500}{1000}=\frac{1}{2}$
Standard 11
Physics