Helium gas goes through a cycle ABCDA (consis | vedclass

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Question

Heat given to system $=\left(n C_{V} \Delta T\right)_{A \rightarrow B}+\left(b C_{P} \Delta T\right)_{B \rightarrow C}$

$=\left[\frac{3}{2}(n R \De

Vedclass · Accepted Answer

$15.4$

Vedclass · Answer

Heat given to system $=\left(n C_{V} \Delta Tight)_{A ightarrow B}+\left(b C_{P} \Delta Tight)_{B ightarrow C}$

$=\left[\frac{3}{2}(n R \Delta T)ight]_{A ightarrow B}+\left[\frac{5}{2}(n R \Delta T)ight]_{B, ightarrow C}$

$\left[\frac{3}{2} 	imes V_{0} \Delta Pight]_{A ightarrow B}+\left[\frac{5}{2} 	imes 2 P_{0} 	imes V_{0}ight]$

$=\frac{13}{2} P_{0} V_{0}$

and $W_{0}=P_{0} V_{0}$

$\eta=W$ or $\frac{k}{	ext { heatgiven }}=\frac{P-0 V_{0}}{\frac{13}{2} P_{0} V_{0}} 	imes 100=15.4 \%$

Helium gas goes through a cycle $ABCDA$ (consisting of two isochoric and two isobaric lines) as shown in figure. Efficiency of this cycle is nearly ..... $\%$ (Assume the gas to be close to ideal gas)

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