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9-1.Fluid Mechanics
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An ice berg of density $900 Kg/m^3$ is floating in water of density $1000 Kg/m^3$. The percentage of volume of ice-cube outside the water is ...... $\%$
A
$20$
B
$35$
C
$10$
D
$25$
Solution
(c) Let the total volume of ice-berg is $V$ and its density is $\rho$. If this ice-berg floats in water with volume Vin inside it then ${V_{in}}\sigma g = V\rho g$ ==> ${V_{in}} = \left( {\frac{\rho }{\sigma }} \right)\;V$[$\sigma = $density of water]
or ${V_{out}} = V – {V_{in}} = \left( {\frac{{\sigma – \rho }}{\sigma }} \right)\;V$
==> $\frac{{{V_{out}}}}{V} = \left( {\frac{{\sigma – \rho }}{\sigma }} \right) = \frac{{1000 – 900}}{{1000}} = \frac{1}{{10}}$
${V_{out}} = 10\% $ of $V$
Standard 11
Physics
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