An ideal gas of density $\rho=0.2 kg m ^{-3}$ enters a chimney of height $h$ at the rate of $\alpha=0.8 kg s ^{-1}$ from its lower end, and escapes through the upper end as shown in the figure. The cross-sectional area of the lower end is $A_1=0.1 m ^2$ and the upper end is $A_2=0.4 m ^2$. The pressure and the temperature of the gas at the lower end are $600 Pa$ and $300 K$, respectively, while its temperature at the upper end is $150 K$. The chimney is heat insulated so that the gas undergoes adiabatic expansion. Take $g=10 ms ^{-2}$ and the ratio of specific heats of the gas $\gamma=2$. Ignore atmospheric pressure.

Which of the following statement($s$) is(are) correct?

224347-q

  • [IIT 2022]
  • A

    The pressure of the gas at the upper end of the chimney is $300 Pa$.

  • B

    The velocity of the gas at the lower end of the chimney is $40 ms ^{-1}$ and at the upper end is $20 ms ^{-1}$.

  • C

    The height of the chimney is $590 m$.

  • D

    The density of the gas at the upper end is $0.05 kg m ^{-3}$.

Similar Questions

Two moles of an ideal monoatomic gas at ${27^o}C$ occupies a volume of $V.$ If the gas is expanded adiabatically to the volume $2V,$ then the work done by the gas will be ....... $J$ $[\gamma = 5/3,\,R = 8.31J/mol\,K]$

A given ideal gas with $\gamma  = \frac{{{C_p}}}{{{C_v}}} = 1.5$ at a temperature $T$. If the gas is compressed adiabatically to one-fourth of its initial volume, the final temperature will be ..... $T$

  • [AIEEE 2012]

Write equation for work done for compression for an ideal gas.

The equation of state for a gas is given by $PV = nRT + \alpha V$, where $n$ is the number of moles and $\alpha $ is a positive constant. The initial temperature and pressure of one mole of the gas contained in a cylinder are $T_o$ and $P_o$ respectively. The work done by the gas when its temperature doubles isobarically will be

  • [JEE MAIN 2014]

Adiabatic modulus of elasticity of a gas is $2.1 \times {10^5}N/{m^2}.$ What will be its isothermal modulus of elasticity $\left( {\frac{{{C_p}}}{{{C_v}}} = 1.4} \right)$