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2. Electric Potential and Capacitance
medium
An infinite non-conducting sheet has a surface charge density $\sigma = 0.10\, \mu C/m^2$ on one side. How far apart are equipotential surfaces whose potentials differ by $50\, V$
A
$8.85\, m$
B
$8.85\, cm$
C
$8.85\, mm$
D
$88.5\, mm$
Solution
(c) $E = \frac{V}{d}$ $==>$ $\frac{\sigma }{{2{\varepsilon _0}}} = \frac{V}{d}$ $==>$ $d = \frac{{V \times 2{\varepsilon _0}}}{\sigma }$ $ = \frac{{50 \times 2 \times 8.85 \times {{10}^{ – 12}}}}{{0.1 \times {{10}^{ – 6}}}}$
$= 8.85 \times 10^{-3} \,m = 8.88\, mm$
Standard 12
Physics