An iron ball of mass 0.2,kg is heated to 10,^oC and put into a block of ice at 0,^oC. 25,g of ice me

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10-1.Thermometry, Thermal Expansion and Calorimetry

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An iron ball of mass $0.2\,kg$ is heated to $10\,^oC$ and put into a block of ice at $0\,^oC.$ $25\,g$ of ice melts. If the latent heat of fusion of ice is $80\,cal/g,$ then the specific heat of iron in $cal/g\,^oC$ is

A

$1$

B

$0.1$

C

$0.8$

D

$0.08$

Solution

Heat taken $=$ Heat given

or $\quad \mathrm{Ms} \Delta \theta=\mathrm{mL}$

$(200)(s)(100)=25 \times 80$

$s=0.1 \mathrm{cal} / \mathrm{g}^{\circ} \mathrm{C}$

Standard 11

Physics

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