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An object is moving along a straight line with uniform acceleration. The following table gives the velocity of the object at various instants of time
| Time $(s)$ | $0$ | $1$ | $2$ | $3$ | $4$ | $5$ | $6$ |
| Velocity $\left( m s ^{-1}\right)$ | $2$ | $4$ | $6$ | $8$ | $10$ | $12$ | $14$ |
Plot the graph.
From the graph.
$(i)$ Find the velocity of the object at the end of $2.5 sec$
$(ii)$ Calculate the acceleration.
$(iii)$ Calculate' the distance covered in the last $4$ sec.
Solution
$(i)$ $v=7 m s ^{-1}$
$(ii)$ $\quad a=\frac{v-u}{t}=\frac{14-2}{6}=2 m s ^{-2}$
$(iii)$ $S =$ Area under the graph
$=$ Area of the trapezium $ABCD$
$=\frac{1}{2}[ AD + BC] \times CD$
$=\frac{1}{2}[6+14] \times 4=40 m$
Similar Questions
A truck is moving on a straight road with uniform acceleration. The following table gives the speed of the truck at various instants of time.
| Speed $\left(m s^{-1}\right)$ | $5$ | $10$ | $15$ | $20$ | $25$ | $30$ |
| Time $(s)$ | $0$ | $10$ | $20$ | $30$ | $40$ | $50$ |
Draw the speed-time graph by choosing a convenient scale. Determine from it
$(i)$ the acceleration of truck
$(ii)$ the distance travelled by the truck in $50$ seconds.
