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3-2.Motion in Plane
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An object is moving on a circular track of radius $450\, m$. At some instant, the object is moving at $30\, m/s$ and gaining speed at a uniform rate of $2 m/s^2$. Its acceleration at this instant is nearly .......... $m/s^2$
A$1.6$
B$0.8$
C$2.8$
D$3.4$
Solution
$\mathrm{a}=\sqrt{\mathrm{a}_{\mathrm{c}}^{2}+\mathrm{a}_{\mathrm{t}}^{2}}=\sqrt{\left(\frac{\mathrm{V}^{2}}{\mathrm{r}}\right)^{2}+\mathrm{a}_{\mathrm{t}}^{2}}$
$a=\sqrt{\left(\frac{900}{450}\right)^{2}+(2)^{2}}=2.8 \mathrm{m} / \mathrm{s}^{2}$
$a=\sqrt{\left(\frac{900}{450}\right)^{2}+(2)^{2}}=2.8 \mathrm{m} / \mathrm{s}^{2}$
Standard 11
Physics
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