Gujarati
3-2.Motion in Plane
medium

An object is thrown along a direction inclined at an angle of ${45^o}$ with the horizontal direction. The horizontal range of the particle is equal to

A

Vertical height

B

Twice the vertical height

C

Thrice the vertical height

D

Four times the vertical height

Solution

(d) $R = 4H\cot \theta $

if $\theta = 45^\circ $ then $R = 4H\cot (45^\circ ) = 4H$

Standard 11
Physics

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