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3-2.Motion in Plane
medium
An object is thrown along a direction inclined at an angle of ${45^o}$ with the horizontal direction. The horizontal range of the particle is equal to
A
Vertical height
B
Twice the vertical height
C
Thrice the vertical height
D
Four times the vertical height
Solution
(d) $R = 4H\cot \theta $
if $\theta = 45^\circ $ then $R = 4H\cot (45^\circ ) = 4H$
Standard 11
Physics