4-1.Newton's Laws of Motion
easy

An object with a mass $10\, kg$ moves at a constant velocity of $10 \,m/sec$. A constant force then acts for $4\, second$ on the object and gives it a speed of $2\, m/sec$ in opposite direction, the force acting on the object is ......... $N$

A

$30$

B

$-30$

C

$3$

D

$-3$

Solution

(b)$F = ma = 10 \times ( – 3) = – 30\,N$

Standard 11
Physics

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