A 30, gm bullet initially travelling at 120 ,m/s penetrates 12 ,cm into a wooden block. average resi

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4-1.Newton's Laws of Motion

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A $30\, gm$ bullet initially travelling at $120 \,m/s$ penetrates $12 \,cm$ into a wooden block. The average resistance exerted by the wooden block is ........... $N$

A

$2850$

B

$2200 $

C

$2000$

D

$1800$

Solution

(d)$F = \frac{{m\,({u^2} – {v^2})}}{{2S}} = \frac{{30 \times {{10}^{ – 3}} \times {{(120)}^2}}}{{2 \times 12 \times {{10}^{ – 2}}}} = 1800\,N$

Standard 11

Physics

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