Areversible adiabatic path on a $P-V$ diagram for an ideal gas passes through stateAwhere $P=0$.$7\times 10^5 \,\,N/ m^{-2}$ and $v = 0.0049 \,\,m^3$. The ratio of specific heat of the gas is $1.4$. The slope of path at $A$ is :
$2.0 \times 10^7 \,\,Nm^{-5}$
$1.0 \times 10^7 \,\,Nm^{-5}$
$- 2.0 \times 10^7\,\, Nm^{-5}$
$-1.0 \times 10^7 \,\,Nm^{-5}$
Following figure shows $P-T$ graph for four processes $A, B, C$ and $D$. Select the correct alternative.
The volume of $1\; mole$ of an ideal gas with the adiabatic exponent $\gamma$ is changed according to the relation $V=\frac bT$ where $b =$ constant. The amount of heat absorbed by the gas in the process if the temperature is increased by $\triangle T$ will be
A cyclic process $ABCA$ is shown in $PT$ diagram. When presented on $PV$, it would
In the following $P-V$ diagram two adiabatics cut two isothermals at temperatures $T_1$ and $T_2$ (fig.). The value of $\frac{{{V_a}}}{{{V_d}}}$ will be
A given ideal gas with $\gamma = \frac{{{C_p}}}{{{C_v}}} = 1.5$ at a temperature $T$. If the gas is compressed adiabatically to one-fourth of its initial volume, the final temperature will be ..... $T$