Work of 146 kJ is performed in order to compress one kilo mole of gas adiabatically and in this proc

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11.Thermodynamics

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The work of $146\ kJ$ is performed in order to compress one kilo mole of gas adiabatically and in this process the temperature of the gas increases by $7^o C$. The gas is $(R=8.3\ J\ mol^{-1} K^{-1})$

A

monoatomic

B

diatomic

C

triatomic

D

a mixture of monoatomic and diatomic

(AIEEE-2006)

Solution

$W = \frac{{nR\Delta T}}{{1 – \gamma }} \Rightarrow – 146000 = \frac{{1000 \times 8.3 \times 7}}{{1 – \gamma }}$

$or\,1 – \gamma = – \frac{{58.1}}{{146}} \Rightarrow \gamma = 1 + \frac{{58.1}}{{146}} = 1.4$

Hence the gas is diatomic.

Standard 11

Physics

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