As shown in figure, a 70,kg garden roller is pushed with a force of overrightarrow{ F }=200,N at an

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4-1.Newton's Laws of Motion

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As shown in figure, a $70\,kg$ garden roller is pushed with a force of $\overrightarrow{ F }=200\,N$ at an angle of $30^{\circ}$ with horizontal. The normal reaction on the roller is $.......\,N$ $\left(\right.$ Given $\left.g =10\,m s ^{-2}\right)$

A

$800 \sqrt{2}$

B

$600$

C

$800$

D

$200 \sqrt{3}$

(JEE MAIN-2023)

Solution

$N = mg + F \sin 30^{\circ}$

$=700+200 \times \frac{1}{2}=800 \text { newton }$

Standard 11

Physics

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