4-1.Newton's Laws of Motion
easy

Three blocks are placed as shown in figure. Mass of $A, B$ and $C$ are $m_1, m_2$ and $m_3$ respectively. The force exerted by block ' $C$ ' on ' $B$ ' is .........

A$m_1 g$
B$\left(m_1+m_2\right) g$
C$m_2 g$
D$\left(m_1+m_2+m_3\right) g$

Solution

(b)
$N_2=N_1+m_2 g=m_1 g+m_2 g$
$N_2=\left(m_1+m_2\right) g$
is $N_2$ only $=\left(m_1+m_2\right) g$
Standard 11
Physics

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