Gujarati
4-1.Newton's Laws of Motion
medium

As shown in figure the tension in the horizontal cord is $30 \,N$. The weight $W$ and tension in the string $OA$  in Newton are

A$30 \sqrt 3 ,30$
B$30 \sqrt 3 ,60$
C$60 \sqrt 3 ,30$
DNone of these

Solution

(b) From the figure $T\,\sin {30^°} = 30$ …$(i)$
$T\cos {30^°} = W$…$(ii)$
By solving equation $(i)$ and $(ii)$ we get
$W = 30\sqrt 3\, N$ and $T = 60\,N$
 
Standard 11
Physics

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