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4-1.Newton's Laws of Motion
medium
As shown in figure the tension in the horizontal cord is $30 \,N$. The weight $W$ and tension in the string $OA$ in Newton are
A$30 \sqrt 3 ,30$
B$30 \sqrt 3 ,60$
C$60 \sqrt 3 ,30$
DNone of these
Solution

$T\cos {30^°} = W$…$(ii)$
By solving equation $(i)$ and $(ii)$ we get
$W = 30\sqrt 3\, N$ and $T = 60\,N$
Standard 11
Physics