As shown in figure there is a spring block system. Block of mass 500,g is pressed against a hor

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5.Work, Energy, Power and Collision

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As shown in figure there is a spring block system. Block of mass $500\,g$ is pressed against a horizontal spring fixed at one end to compress the spring through $5.0\,cm$ . The spring constant is $500\,N/m$ . When released, calculate the distance where it will hit the ground $4\,m$ below the spring ? $(g = 10\,m/s^2)$

A

$1\,m$

B

$\sqrt 2\,m$

C

$\sqrt 3\,m$

D

$4\,m$

Solution

$C.O.M.E.$

$\frac{1}{2} \mathrm{kx}^{2}=\frac{1}{2} \mathrm{mv}^{2}$

$V=\sqrt{\frac{k x^{2}}{m}}$

Time of flight $t=\sqrt{\frac{2 \mathrm{H}}{\mathrm{g}}}$

Horizontal dist. $=\mathrm{vt}$

$=\sqrt{\frac{\mathrm{kx}^{2}}{\mathrm{m}}} \times \sqrt{\frac{2 \mathrm{H}}{\mathrm{g}}}$

$=\sqrt{\frac{500 \times(.05)^{2}}{0.5}} \times \sqrt{\frac{2 \times 4}{10}}=\sqrt{2} \mathrm{m}$

Standard 11

Physics

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