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1. Electric Charges and Fields
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If potential at centre of uniformaly charged ring is $V_0$ then electric field at its centre will be (assume radius $=R$ )
A
$\frac{{{V_0}}}{R}$
B
$\frac{{{3V_0}}}{2R}$
C
$\frac{{{V_0}}}{2R}$
D
Zero
Solution

$\mathrm{E}=\frac{\mathrm{KQx}}{\left(\mathrm{R}^{2}+\mathrm{x}^{2}\right)^{3 / 2}}$
at center $x=0$
$\mathrm{E}_{\text {center }}=0$
Standard 12
Physics
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