Gujarati
Hindi
1. Electric Charges and Fields
normal

If potential at centre of uniformaly charged ring is $V_0$ then electric field at its centre will be (assume radius $=R$ )

A

$\frac{{{V_0}}}{R}$

B

$\frac{{{3V_0}}}{2R}$

C

$\frac{{{V_0}}}{2R}$

D

Zero

Solution

$\mathrm{E}=\frac{\mathrm{KQx}}{\left(\mathrm{R}^{2}+\mathrm{x}^{2}\right)^{3 / 2}}$

at center $x=0$

$\mathrm{E}_{\text {center }}=0$

Standard 12
Physics

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