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7.Gravitation
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Assuming earth to be a sphere of a uniform density, what is the value of gravitational acceleration in a mine $100\, km$ below the earth’s surface ........ $m/{s^2}$. (Given $R = 6400 \,km$)
A
$9.66$
B
$7.64$
C
$5.06$
D
$3.10$
Solution
(a)$g' = g\,\left( {1 – \frac{d}{R}} \right) = 9.8\,\left( {1 – \frac{{100}}{{6400}}} \right) = 9.66\,m/{s^2}$
Standard 11
Physics