7.Gravitation
medium

The angular speed of earth, so that the object on equator may appear weightless, is $(g = 10\,m/{s^2}$, radius of earth $6400\, km$)

A

$1.25 \times {10^{ - 3}}\,rad/sec$

B

$1.56 \times {10^{ - 3}}\,rad/sec$

C

$1.25 \times {10^{ - 1}}\,rad/sec$

D

$1.56\; rad/sec$

(AIIMS-2011)

Solution

(a) For condition of weightlessness of equator $\omega = \sqrt {\frac{g}{R}} = \frac{1}{{800}} = 1.25 \times {10^{ – 3}}\frac{{rad}}{s}$

Standard 11
Physics

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