At 0,^oC , value of density of fixed mass of an ideal gas divided by its pressure is x . At 100,^oC

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12.Kinetic Theory of Gases

normal

At $0\,^oC$ , the value of the density of fixed mass of an ideal gas divided by its pressure is $x$ . At $100\,^oC$ , this value will be

$\frac {100}{273}\, x$

$\frac {273}{100}\, x$

$\frac {273}{373}\, x$

$x$

Solution

$\mathrm{PV}=\mathrm{nRT}$

$\mathrm{P} \times \frac{\mathrm{M}}{\rho}=\frac{\mathrm{M}}{\mathrm{M}_{\mathrm{W}}} \mathrm{RT}$

$\frac{\mathrm{P}}{\rho}=\frac{\mathrm{RT}}{\mathrm{M}_{\mathrm{w}}}=\frac{1}{\mathrm{x}}$ (given)

$\frac{\mathrm{R}(273)}{\mathrm{M}_{\mathrm{w}}}=\frac{1}{\mathrm{x}} \quad$ and $, \quad \frac{\mathrm{R}(373)}{\mathrm{M}_{\mathrm{W}}}=\frac{1}{\mathrm{x}_{2}}$

On dividing $\&$ solving

$\mathrm{x}_{2}=\frac{273}{373} \mathrm{x}$

Standard 11

Physics

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normal

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normal

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normal

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hard

At $0\,^oC$ , the value of the density of fixed mass of an ideal gas divided by its pressure is $x$ . At $100\,^oC$ , this value will be

Solution

Similar Questions

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A gas mixture consists of molecules of type $1, 2$ and $3$, with molar masses $m_1 > m_2 > m_3$. $v_{rms}$ and $ \bar K$ are the $r.m.s.$ speed and average kinetic energy of the gases. Which of the following is true?

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