Gujarati
Hindi
13.Nuclei
medium

At $t = 0$, number of active nuclei in a sample is $N_0$. How much no. of nuclei will decay in time between its first mean life and second half life?

A

$\frac{{{N_0}}}{e}$

B

$\frac{{{N_0}}}{e} - \frac{{{N_0}}}{4}$

C

$\frac{{{N_0}}}{2} - \frac{{{N_0}}}{e}$

D

$\frac{{{N_0}}}{4}$

Solution

At $\mathrm{t}=\mathrm{T}_{\mathrm{m}}, \quad \mathrm{N}_{1}=\frac{\mathrm{N}_{0}}{\mathrm{e}}$

At $\mathrm{t}=2 \mathrm{T}_{1 / 2} \quad \mathrm{N}_{2}=\frac{\mathrm{N}_{0}}{4}$

So no. of decay $=N_{1}-N_{2}$

Standard 12
Physics

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