There are 10^{10} radioactive nuclei in a giv | vedclass

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Question

$\frac{{N}}{{N}_{0}}=\left(\frac{1}{2}\right)^{\frac{{t}}{t_{\frac{1}{2}}}}$

$\frac{{N}}{10^{10}}=\left(\frac{1}{2}\right)^{\frac{30}{60}}$

${N}

Vedclass · Accepted Answer

$7 	imes 10^{9}$

Vedclass · Answer

$\frac{{N}}{{N}_{0}}=\left(\frac{1}{2}ight)^{\frac{{t}}{t_{\frac{1}{2}}}}$

$\frac{{N}}{10^{10}}=\left(\frac{1}{2}ight)^{\frac{30}{60}}$

${N}=10^{10} 	imes\left(\frac{1}{2}ight)^{\frac{1}{2}}=\frac{10^{10}}{\sqrt{2}} \approx 7 	imes 10^{9}$

There are $10^{10}$ radioactive nuclei in a given radioactive element, Its half-life time is $1\, minute.$ How many nuclei will remain after $30\, seconds?$

$(\sqrt{2}=1.414)$

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