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7.Gravitation
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At a height of $10 \,km$ above the surface of earth, the value of acceleration due to gravity is the same as that of a particular depth below the surface of earth. Assuming uniform mass density for the earth, the depth is ............. $km$
A
$1$
B
$5$
C
$10$
D
$20$
(KVPY-2020)
Solution
(d)
The value of acceleration due to gravity at a height $h$ is
$g_h=g\left(1-\frac{2 h}{R}\right)$
and at depth $d$ is
$g_d=g\left(1-\frac{d}{R}\right)$
It is given that, $g_h=g_d$
$\Rightarrow \quad g\left(1-\frac{2 h}{R}\right)=g\left(1-\frac{d}{R}\right)$
$\Rightarrow \quad \frac{2 h}{R}=\frac{d}{R}$
$\Rightarrow \quad d=2 h=2 \times 10 \quad(\because h=10 \,km )$
$=20 \,km$
Standard 11
Physics
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