At time $t=0$ is particle starts moving along the $x-$axis. If its kinetic energy increases uniformly with time $t$, the net force acting on it must be proportional to
$\sqrt{t}$
$t$
$\frac{1}{\sqrt{t}}$
constant
The kinetic energy of a body of mass $3 \,kg$ and momentum $2 \,N-s$ is
A stationary particle breaks into two parts of masses $m_A$ and $m_B$ which move with velocities $v_A$ and $V_B$ respectively. The ratio of their kinetic energies $\left(\mathrm{K}_B: \mathrm{K}_{\mathrm{A}}\right)$ is :
A light and a heavy body have equal momenta. Which one has greater K.E
$A$ ball is projected vertically upwards. Air resistance variation in $g$ may be neglected. The ball rises to its maximum height $H$ in a time $T$, the height being $h$ after a time $t$
$[1]$ The graph of kinetic energy $E_k$ of the ball against height $h$ is shown in figure $1$
$[2]$ The graph of height $h$ against time $t$ is shown in figure $2$
$[3]$ The graph of gravitational energy $E_g$ of the ball against height $h$ is shown in figure $3$
Which of $A, B, C, D, E$ shows the correct answers?
If the K.E. of a particle is doubled, then its momentum will