Boron is unable to form BF_{6}^{3-} on. Explain.

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p-Block Elements - I

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Boron is unable to form $BF_{6}^{3-}$ on. Explain.

Option A

Option B

Option C

Option D

Solution

Due to non-availability of $d$ orbitals, boron is unable to expand its octet. Therefore the maximum covalence of boron cannot exceed $4$.

Standard 11

Chemistry

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