Cards are drawn one by one without replacement from a pack of $52$ cards. The probability that $10$ cards will precede the first ace is
$\frac{{241}}{{1456}}$
$\frac{{164}}{{4165}}$
$\frac{{451}}{{884}}$
None of these
A set $S$ contains $7$ elements. A non-empty subset $A$ of $S$ and an element $x$ of $S$ are chosen at random. Then the probability that $x \in A$ is
‘$A$’ draws two cards with replacement from a pack of $52$ cards and ‘$B$' throws a pair of dice what is the chance that ‘$A$’ gets both cards of same suit and ‘$B$’ gets total of $6$
Let $\quad S =\left\{ M =\left[ a _{ ij }\right], a _{ ij } \in\{0,1,2\}, 1 \leq i , j \leq 2\right\}$ be a sample space and $A=\{M \in S: M$ is invertible $\}$ be an event. Then $P ( A )$ is equal to
The chance of getting a doublet with $2$ dice is
In a single throw of two dice the probability of obtaining an odd number is