- Home
- Standard 11
- Physics
3-2.Motion in Plane
medium
Centripetal acceleration of a cyclist completing $7$ rounds in a minute along a circular track of radius $5 \,m$ with a constant speed, is ......... $m / s ^2$
A$2.7$
B$4$
C$3.78$
D$6$
Solution
(a)
Centripetal acceleration $= V ^2 / r$
$V =$ Distance $/$ time.
$7$ revolutions per minute.
$1$ revolution $=2 \times 3.142 \times 5=31.42\, m$
$7$ revolutions $=7 \times 22 / 7 \times 2 \times 5=220\, m$
$220\,m$ in $60$ second
In one second we have :
$=3.667\,m / s$
Centripetal acceleration $=3.667^2 / 5=2.689\, m / s ^2$
Hence, Option $A$ is correct.
Centripetal acceleration $= V ^2 / r$
$V =$ Distance $/$ time.
$7$ revolutions per minute.
$1$ revolution $=2 \times 3.142 \times 5=31.42\, m$
$7$ revolutions $=7 \times 22 / 7 \times 2 \times 5=220\, m$
$220\,m$ in $60$ second
In one second we have :
$=3.667\,m / s$
Centripetal acceleration $=3.667^2 / 5=2.689\, m / s ^2$
Hence, Option $A$ is correct.
Standard 11
Physics
