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11.Thermodynamics
normal
Compressed air in the tube of a wheel of a cycle at normal temperature suddenly starts coming out from a puncture. The air inside
A
Starts becoming hotter
B
Remains at the same temperature
C
Starts becoming cooler
D
May become hotter or cooler depending upon the amount of water vapour present
Solution
Since tube is punctured suddenly, the process is adiabatic.
In adiabatic process : $TV ^{\gamma-1}=$ constant
$\frac{ T _2}{ T _1}=\left(\frac{ V _1}{ V _2}\right)^{\gamma-1}$
since air is expanding,
$V _2 > V _1$
$\therefore T _1 > T _2$
Standard 11
Physics