Gujarati
Hindi
11.Thermodynamics
normal

A cyclic process $ABCA$ is shown in $PT$ diagram. When presented on $PV$, it would be

A
B
C
D

Solution

$A \rightarrow B \Rightarrow P$ constant $\& T \downarrow$ So $V \downarrow$

$\mathrm{B} \rightarrow \mathrm{C} \Rightarrow \mathrm{T}$ constant $\& \mathrm{P} \downarrow$ So $\mathrm{V} \uparrow$

$\mathrm{C} \rightarrow \mathrm{A} \Rightarrow \mathrm{V}$ constant $\& \mathrm{PT}$ So $\mathrm{T} \uparrow$

Standard 11
Physics

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