Consider a vector F =4 hat{ i }-3 hat{ j } . Another vector perpendicular of F is

English

Gujarati

Hindi

3-1.Vectors

normal

Consider a vector $F =4 \hat{ i }-3 \hat{ j }$. Another vector perpendicular of $F$ is

$4 \hat{ i }+3 \hat{ j }$

$6 \hat{ i }$

$7 \hat{ k }$

$3 \hat{ i }-4 \hat{ j }$

Solution

(c)

The vector perpendicular to the $i$ and $j$ plane would be along the unit vector $k$. Another vector in $i$ and $j$ plane can be perpendicular to $\overrightarrow{ F }$

$(3 \hat{i}+4 \hat{j}) \perp(4 \hat{i}-3 \hat{j})$

But, from the options only $7 \hat{ k } \perp(4 \hat{i}-3 \hat{ j })$

Standard 11

Physics

A force of $5 N$ acts on a particle along a direction making an angle of $60^{\circ}$ with vertical. Its vertical component will be $………\,N$

normal

Figure shows three vectors $p , q$ and $r$, where $C$ is the mid point of $A B$. Then, which of the following relation is correct?

normal

The resultant of $A$ and $B$ makes an angle $\alpha$ with $A$ and $\beta$ with $B$, then

normal

A vector $\overrightarrow a $ is turned without a change in its length through a small angle $d\theta .$The value of $|\Delta \overrightarrow a |$ and $\Delta a$ are respectively

normal

The component of vector $\vec A = 2\hat i + 3\hat j$ along the vector $\hat i + \hat j$ is

normal

Consider a vector $F =4 \hat{ i }-3 \hat{ j }$. Another vector perpendicular of $F$ is

Solution

Similar Questions

A force of $5 N$ acts on a particle along a direction making an angle of $60^{\circ}$ with vertical. Its vertical component will be $………\,N$

Figure shows three vectors $p , q$ and $r$, where $C$ is the mid point of $A B$. Then, which of the following relation is correct?

The resultant of $A$ and $B$ makes an angle $\alpha$ with $A$ and $\beta$ with $B$, then

A vector $\overrightarrow a $ is turned without a change in its length through a small angle $d\theta .$The value of $|\Delta \overrightarrow a |$ and $\Delta a$ are respectively

The component of vector $\vec A = 2\hat i + 3\hat j$ along the vector $\hat i + \hat j$ is

Start a Free Trial Now