Consider a water jar of radius $R$ that has water filled up to height $H$ and is kept on a stand of height $h$ (see figure). Through a hole of radius $r(r < < R)$ at its bottom, the water leaks out and the stream of water coming down towards the ground has a shape like a funnel as shown in the figure. If the radius of the cross-section of water stream when it hits the ground is $x$. Then
$x = r{\left( {\frac{H}{{H + h}}} \right)^2}$
$x = r{\left( {\frac{H}{{H + h}}} \right)^{\frac{1}{2}}}$
$x = r\left( {\frac{H}{{H + h}}} \right)$
$x = r{\left( {\frac{H}{{H + h}}} \right)^{\frac{1}{4}}}$
A manometer reads the pressure of a gas in an enclosure as shown in the figure.
The absolute and gauge pressure of the gas in $cm$ of mercury is
(Take atmospheric pressure $= 76\,cm$ of mercury)
If the terminal speed of a sphere of gold (density $\ =\ 19.5 × 10^3\ kg/m^3$ ) is $0.2\ m/s$ in a viscous liquid (density $\ =\ 1.5 × 10^3\ kg/m^3$ ), find the terminal speed of a sphere of silver (density $\ =\ 10.5 × 10^3\ kg/m^3$ ) of the same size in the same liquid ....... $m/s$
Two drops of equal radius are falling through air with a steady velocity of $5\,cm/s$. If the two drops coalesce, then its terminal velocity will be
The height of water in a tank is $H$. The range of the liquid emerging out from a hole in the wall of the tank at a depth $\frac {3H}{4}$ form the upper surface of water, will be
A spherical solid ball of volume $V$ is made of a material of density ${\rho _1}$ . It is falling through a liquid of density ${\rho _2}\left( {{\rho _2} < {\rho _1}} \right)$. Assume that the liquid applies a viscous force on the ball that is propoertional to the square of its speed $v$ , i.e., ${F_{{\rm{viscous}}}} = - k{v^2}\left( {k > 0} \right)$. Then terminal speed of the bal is