Gujarati
Hindi
9-1.Fluid Mechanics
normal

Air is blowing across the horizontal wings of an aeroplane is such a way that its speeds below and above wings are $90\, m/s$ and $120\, m/s$ respectively. If density of air is $1.3\, kg/m^3$, then the pressure difference between lower and upper sides of wings will be ........ $N/m^2$

A

$4819$

B

$481.90$

C

$409.5$

D

$4095$

Solution

Pressure difference ${P_2} – {P_1} = \frac{\rho }{2}\,\left( {V_1^2 – V_2^2} \right)$

(According to Bernoulli's theorem)

Standard 11
Physics

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