Consider an initially neutral hollow conducting spherical shell with inner radius $r$ and outer radius $2 r$. A point charge $+Q$ is now placed inside the shell at a distance $r / 2$ from the centre. The shell is then grounded by connecting the outer surface to the earth. $P$ is an external point at a distance $2 r$ from the point charge $+Q$ on the line passing through the centre and the point charge $+Q$ as shown in the figure. The magnitude of the force on a test charge $+q$ placed at $P$ will be
$\frac{1}{4 \pi \varepsilon_0} \frac{q Q}{4 r^2}$
$\frac{1}{4 \pi \varepsilon_0} \frac{9 q Q}{100 r^2}$
$\frac{1}{4 \pi \varepsilon_0} \frac{4 q Q}{25 r^2}$
$0$
A hollow closed conductor of irregular shape is given some charge. Which of the following statements are correct ?
If $q$ is the charge per unit area on the surface of a conductor, then the electric field intensity at a point on the surface is
A metallic spherical shell has an inner radius ${{\rm{R}}_1}$ and outer radius ${{\rm{R}}_2}$. A charge $\mathrm{Q}$ is placed at the centre of the spherical cavity. What will be surface charge density on $(i)$ the inner surface, and $(ii)$ the outer surface ?
‘Inside a conductor electrostatic field is zero’. Explain.
Assertion : In a cavity within a conductor, the electric field is zero.
Reason : Charges in a conductor reside only at its surface