Consider the reaction between chlorine and nitric oxide

$Cl _{2}( g )+2 NO ( g ) \rightarrow 2 NOCl ( g )$

On doubling the concentration of both reactants, the rate of the reaction increases by a factor of $8 .$ However, if only the concentration of $C l_{2}$ is doubled, the rate increases by a factor of $2 .$ The order of this reaction with respect to $NO$ is :

The rate law for the reaction below is given by the expression $k\left[ A \right]\left[ B \right]$ 

                                          $A + B \to$ Product 

If the concentration of $B$ is increased from $0.1$ to $0.3\, mole$, keeping the value of $A$ at $0.1\, mole$, the rate constant will be

Consider a reaction $\mathrm{aG}+\mathrm{bH} \rightarrow$ Products. When concentration of both the reactants $\mathrm{G}$ and $\mathrm{H}$ is doubled, the rate increases by eight times. However, when concentration of $\mathrm{G}$ is doubled keeping the concentration of $\mathrm{H}$ fixed, the rate is doubled. The overall order of the reaction is

$A + 2B \to C$, the rate equation for this reaction is given as Rate $= K[A][B]$ . If the concentration of $A$ is kept the same but that of $B$ is doubled what will happen to the rate it self ?

If doubling the initial concentration of reactant doubles $t_{1/2}$ of reaction, the order of reaction is

For the reaction,

$2{N_2}{O_5}\, \to \,4N{O_2}\, + \,{O_2}$

the rate of reaction is