$A + 2B \to C$, the rate equation for this reaction is given as Rate $= K[A][B]$ . If the concentration of $A$ is kept the same but that of $B$ is doubled what will happen to the rate it self ?
halved
the same
doubled
quadrupled
From the rate expression for the following reactions, determine their order of reaction and the dimensions of the rate constants.
$(i)$ $3 NO ( g ) \rightarrow N _{2} O$ $(g)$ Rate $=k[ NO ]^{2}$
If doubling the initial concentration of reactant doubles $t_{1/2}$ of reaction, the order of reaction is
Write unit of rate constant of following reaction :
$1.$ zero order
$2.$ second order
The experimental data for decomposition of $N _{2} O _{5}$
$\left[2 N _{2} O _{5} \rightarrow 4 NO _{2}+ O _{2}\right]$
in gas phase at $318 \,K$ are given below:
$t/s$ | $0$ | $400$ | $800$ | $1200$ | $1600$ | $2000$ | $2400$ | $2800$ | $3200$ |
${10^2} \times \left[ {{N_2}{O_5}} \right]/mol\,\,{L^{ - 1}}$ | $1.63$ | $1.36$ | $1.14$ | $0.93$ | $0.78$ | $0.64$ | $0.53$ | $0.43$ | $0.35$ |
$(i)$ Plot $\left[ N _{2} O _{5}\right]$ against $t$
$(ii)$ Find the half-life period for the reaction.
$(iii)$ Draw a graph between $\log \left[ N _{2} O _{5}\right]$ and $t$
$(iv)$ What is the rate law $?$
$(v)$ Calculate the rate constant.
$(vi)$ Calculate the half-life period from $k$ and compare it with $(ii)$.
Diazonium salt decomposes as ${C_6}{H_5}N_2^ + C{l^ - } \to {C_6}{H_5}Cl + {N_2}$ At ${0\,^o}C$, the evolution of ${N_2}$ becomes two times faster when the initial concentration of the salt is doubled. Therefore, it is