Gujarati
Hindi
4-1.Newton's Laws of Motion
medium

Consider the shown arrangement. Assume all surfaces to be smooth. If $N$ represents magnitudes of normal reaction between block and wedge, then acceleration of $M$ along horizontal equals

A$\frac{{N\,\sin \theta }}{M}$ along + ve $x-axis$
B$\frac{{N\,\cos \theta }}{M}$ along - ve $x-axis$
C$\frac{{N\,\sin \theta }}{M}$ along - ve $x-axis$
D$\frac{{N\,\sin \theta }}{m+M}$ along + ve $x-axis$

Solution

$\alpha=\frac{N \sin \theta}{M}$ $along -ve$ $x-a x i s$
Standard 11
Physics

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