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10-1.Thermometry, Thermal Expansion and Calorimetry
medium
Density of substance at $0°C$ is $10\, gm/cc$ and at $100°C,$ its density is $9.7\, gm/cc$. The coefficient of linear expansion of the substance will be
A
$10^2$
B
$10^{-2}$
C
$10^{-3}$
D
$10^{-4}$
Solution
(d) Coefficient of volume expansion
$\gamma = \frac{{\Delta \rho }}{{\rho .\Delta T}} = \frac{{({\rho _1} – {\rho _2})}}{{\rho .(\Delta \theta )}} = \frac{{(10 – 9.7)}}{{10 \times (100 – 0)}} = 3 \times {10^{ – 4}}$
Hence, coefficient of linear expansion
$\alpha = \frac{\gamma }{3} = {10^{ – 4}}°C^{-1}$
Standard 11
Physics
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