Gujarati
1. Electric Charges and Fields
easy

Dielectric constant of pure water is $81$. Its permittivity will be

A

$7.12 \times {10^{ - 10}}\,MKS$ units

B

$8.86 \times {10^{ - 12}}MKS$ units

C

$1.02 \times {10^{13}}\;MKS$ units

D

Cannot be calculated

Solution

(a) $\varepsilon = K{\varepsilon _0} = 81 \times 8.854 \times {10^{ – 12}}$$ = 7.17 \times {10^{ – 10}}\,MKS\,units$

Standard 12
Physics

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