Gujarati
Hindi
1. Electric Charges and Fields
medium

In given diagram. Find distance of neutral point from particle of charge $e$ is......$cm$

A

$20$

B

$10$

C

$15$

D

$7.5$

Solution

$\mathrm{x}=\frac{\mathrm{r} \sqrt{\mathrm{q}_{1}}}{\sqrt{\mathrm{q}_{1}}+\sqrt{\mathrm{q}_{2}}} \mathrm{\,x}$ is distance from $\mathrm{q}_{1}.$

$\mathrm{x}=\frac{30 \sqrt{\mathrm{e}}}{\sqrt{\mathrm{e}}+\sqrt{9 \mathrm{e}}}=\frac{30}{3}=10 \mathrm{\,cm}$ from $\mathrm{e}$

Standard 12
Physics

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