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1.Units, Dimensions and Measurement
medium
Dimension of electric current is
A$[{M^0}{L^0}{T^{ - 1}}Q]$
B$[M{L^2}{T^{ - 1}}Q]$
C$[{M^2}L{T^{ - 1}}Q]$
D$[{M^2}{L^2}{T^{ - 1}}Q]$
Solution
(a) $I = \frac{Q}{t} = \frac{{[Q]}}{{[T]}} = [{M^0}{L^0}{T^{ – 1}}Q]$
Standard 11
Physics
