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1.Units, Dimensions and Measurement
medium
Dimensional formula for latent heat is
A${M^0}{L^2}{T^{ - 2}}$
B$ML{T^{ - 2}}$
C$M{L^2}{T^{ - 2}}$
D$M{L^2}{T^{ - 1}}$
(IIT-1983)
Solution
a) $Q = mL \Rightarrow L = \frac{Q}{m}$ (Heat is a form of energy)
= $\frac{{M{L^2}{T^{ – 2}}}}{M} = [{M^0}{L^2}{T^{ – 2}}]$
= $\frac{{M{L^2}{T^{ – 2}}}}{M} = [{M^0}{L^2}{T^{ – 2}}]$
Standard 11
Physics
