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1.Units, Dimensions and Measurement
medium
The dimensions of electric potential are
A$[M{L^2}{T^{ - 2}}{Q^{ - 1}}]$
B$[ML{T^{ - 2}}{Q^{ - 1}}]$
C$[M{L^2}{T^{ - 1}}Q]$
D$[M{L^2}{T^{ - 2}}Q]$
Solution
(a) $V = \frac{W}{Q} = [M{L^2}{T^{ – 2}}{Q^{ – 1}}]$
Standard 11
Physics
Similar Questions
Match List $I$ with List $II$
| List $I$ | List $II$ |
| $A$ Torque | $I$ ${\left[\mathrm{M}^1 \mathrm{~L}^1 \mathrm{~T}^{-2} \mathrm{~A}^{-2}\right]}$ |
| $B$ Magnetic fileld | $II$ $\left[\mathrm{L}^2 \mathrm{~A}^1\right]$ |
| $C$ Magnetic moment | $III$ ${\left[\mathrm{M}^1 \mathrm{~T}^{-2} \mathrm{~A}^{-1}\right]}$ |
| $D$ Permeability of free space | $IV$ $\left[\mathrm{M}^1 \mathrm{~L}^2 \mathrm{~T}^{-2}\right]$ |
