Dimensional formula for pressure head is .... | vedclass

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Question

$[	ext { Presure head }]=\frac{[	ext { Pressure }]}{[	ext { Density }] 	imes[ g ]}$
Pressure $=\frac{	ext { F orce }}{	ext { Area }}$
But,Forc

Vedclass · Accepted Answer

$[ M ^0 L ^1 T ^0]$

Vedclass · Answer

$[	ext { Presure head }]=\frac{[	ext { Pressure }]}{[	ext { Density }] 	imes[ g ]}$
Pressure $=\frac{	ext { F orce }}{	ext { Area }}$
But,Force $=$ Mass $	imes$ Accelaration $=[ M ]\left[ LT ^{-2}ight]=\left[ MLT ^{-2}ight]$
Then,
$[	ext { Pressure }]=\frac{\left[ MLT ^{-2}ight]}{\left[ L ^2ight]}=\left[ ML ^{-1} T ^{-2}ight]$
[Density $]=\frac{[ Mass ]}{[	ext { V olume }]}=\frac{[ M ]}{\left[ L ^3ight]}= ML ^{-3}$
Now,
$[	ext { Presure head }]=\frac{[	ext { Pressure }]}{[	ext { Density }] 	imes[ g ]}=\frac{\left[ ML ^{-1} T ^{-2}ight]}{\left[ ML ^{-3}ight]\left[ LT ^{-2}ight]}=\left[ M ^0 L ^1 T ^0ight]$

Dimensional formula for pressure head is ............

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